Students will come to know that a polynomial of the form ax2+bx+c, where a, b and c are real numbers and a≠0 is called a quadratic polynomial.
When we equate a quadratic polynomial to a constant, we get a quadratic equation.
Any equation of the form p(x)=c, where p(x) is a polynomial of degree 2 and c is a constant, is a quadratic equation.
The standard form of a quadratic equation is ax2+bx+c=0, where a,b and c are real numbers and a≠0.
‘a’ is the coefficient of x2. It is called the quadratic coefficient. ‘b’ is the coefficient of x. It is called the linear coefficient. ‘c’ is the constant term.
Some important topics to study in this chapter are as follows:
- Factorisation method
- Completing the square method
- Nature of Roots
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Students can view and download the solutions from the link given below.
NCERT Solutions for Chapter 4: Quadratic Equations
Also Check
Chapter 1: Real Numbers
Chapter 2: Polynomials
Chapter 3: Pair of Linear Equations in Two Variables
Chapter 5: Arithmetic Progression
Chapter 6: Triangles
Chapter 7: Coordinate Geometry
Chapter 8: Introduction to Trigonometry
Chapter 9: Some Applications of Trigonometry
Chapter 10: Circle
Chapter 11: Constructions
Chapter 12: Areas Related to Circles
Chapter 13: Surface Areas and Volume
Chapter 14: Statistics
Chapter 15: Probability
Check out Frequently Asked Questions (FAQs) for Chapter 4: Quadratic Equations
The quadratic equation has degree
The cubic equation has degree
A bi-quadratic equation has degree
A natural number, when increased by 12, equals 160 times its reciprocal. Find the number.
Let the number be x
Then according to question,
x + 12 = 160/x
x2 + 12x – 160 = 0
x2 + 20x – 8x – 160 = 0
(x + 20) (x – 8) = 0
x = -20, 8
Since the number is natural, so we consider only positive value.
Rohini had scored 10 more marks in her mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks. How many marks did she get in the test?
Let her actual marks be x
Therefore,
9 (x + 10) = x2
⇒x2 – 9x – 90 = 0
⇒x2 – 15x + 6x – 90 = 0
⇒x(x – 15) + 6 (x – 15) = 0
⇒(x + 6) (x – 15) = 0
Therefore x = – 6 or x =15
Since x is the marks obtained, x ≠ – 6. Therefore, x = 15.